Monday, 27 July 2020

Example ( Analog Communication )

For a light ray which have the wavelength equal to 200 nm, calculate the frequency of the ray.

Solution: As given, in the problem,

Wavelength of the light ray = 200 nm

\lambda = 200 \times 10^{-9} m

Also speed of light,

C = 3 × 10^8 m s{-1}

Substituting these values in the equation above, we get that,

\lambda = \frac {c}{f}

Rearranging the formula,

f = \frac {c}{\lambda}

\frac {3\times 10^8}{200 \times 10^{-9}}

1.5 \times 10^{14} Hz.

The frequency of the wave is equal to 1.5 \times 10^{14} Hz.

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